College Algebra CLEP Practice Exam 2025 – Complete Exam Prep

Question: 1 / 410

What is the root of the quadratic equation 5x^2-14x+9=0?

3, -1

-1.7, -2.3

The given equation is a quadratic equation in the form of ax^2+bx+c=0, where a=5, b=-14, c=9. To find the roots of a quadratic equation, we can use the quadratic formula x=(-b±√(b^2-4ac))/2a. Plugging in the values we get x=(-(-14)±√((-14)^2-4(5)(9)))/2(5), simplifying we get x=(14±√(196-180))/10, which further gives x=(14±√16)/10, x=(14±4)/10. This gives us two possible solutions, x=3 and x=-1. However, since both options A and D have only one positive value, they cannot be the roots of a quadratic equation. On the other hand, option C

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-2.5, 1.5

6, -3

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